No.5 seed Petra Kvitova of the Czech Republic came back from a break down in the second set to claim a 6-1, 6-4 victory over 2009 US Open semifinalist Yanina Wickmayer of Belgium in the first round of the 2018 edition on Tuesday morning.
Kvitova and Wickmayer have had a closely-contested history, with Kvitova holding a slight 5-4 edge, and Wickmayer beat Kvitova en route to the final four at the US Open nine years ago. But in their first meeting since 2013, Kvitova got the job done, reeling off five straight games from 1-4 down to close out the 71-minute tilt.
Former World No.2 Kvitova had 28 winners to Wickmayer’s eight during the match, including eight aces, and the Czech left-hander won nearly 80 percent of points on her vaunted first serve. The Czech has won five titles this year, and is celebrating her second week back in the Top 5 of the WTA rankings since an absence from that cohort dating back to October of 2015.
Two-time Wimbledon champion Kvitova moves into the second round in New York for the seventh consecutive year, where she will face either Wang Yafan of China or Anna Karolina Schmiedlova of Slovakia.
WTATennis.com / photo: Getty Images